The remainder when x100 is
divided by x² – 3x +2 is
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x²-3x+2= ( x-2) ( x-1)
root= 2 and 1
if x^100 is divided then remainder is calculated to
put the value of root one by one in x^100 and
then multiplying both values
or x^100= ( 1 )^100= 1
x^100 = (2)^100
therefore
remainder= 1×2^100= 2^100
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