Question

The remainder when x5+kx2 is divided by (x-1)(x-2)(x-3) contains no terms in x2. Find k

Answer 1

Answer:

K = -6

Step-by-step explanation:

************* HEY DEAR ***************

HERE IS YOUR ANSWER........

=> (X -1)(X -2 )(X - 3) => (X - 1) ( X^2 -5X +6)

                                 => ( X^3  - 5X^2   +  6X - X^2 +5X^3 -6)

                                 => ( 6X^3 - 6X^2 + 6X - 6)..................(1.)

=> NOW,

=>    DIVIDE ( X^5 + KX^2) BY (1.).........................

=>AFTER DIVIDING AM WRITING HERE DIRECTLY

=>REMAINDER WILL BE :

                           ( -5X^5 + 6X^4 -6X^3 + (K + 6)X^2)

=>FROM  THE QUESTION ITS GIVEN THAT REMAINDER HAVE NO TERM OF X^2

=>SO,

               K + 6 = 0

                K = -6..................... ANS.

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Answer 2

Answer:

please write question nicely...

Not able to understand the question

hope u will do it.....