Question

the remainders are in proportion?
f k + 3, k + 2, 3k – 7 and 2k - 3 are in proportion, find k.
y
is the
In hetween x + 2 and x + 9, find the value o​

Answer 1

Answer: - Here, (K + 3/K + 2) = (3k - 7/2k - 3) ⇒ (K + 3) (2K – 3) = (K + 2) (3K – 7). ⇒ 2K2 – 3K + 6K – 9 = 3K2 – 7K + 6K – 14 ⇒ K2 – 4K – 5 = 0 ⇒ (K – 5) (K + 1) = 0 ⇒ K = 5