Question

The reminder on division of x3+2x2+kx+3 by x-3 is 21 , find the quotient and the value of k hence find the zeroes of the cubic polynomial x3 +2x2+ kx-18

Answer 1

ya put the value of x
then x^3+2x^2+kx-18=0
(3^3)+2×(3^2)+k×3-18=0
27+18+3k-18=0
3k= --27
k= --27 / 3
k= --9