Question

The reminder when x²+2x+1 divide (-1)

Answer 1

$\huge\boxed{\tt{ 0 }}$

$\tt{ p(x) = {x}^{2} + 2x + 1 }$

When we substitute (-1) in the place of (x) we get :

$\longrightarrow{\tt{p(-1) = {-1}^{2} + 2(-1) + 1}}$

$\longrightarrow{\tt{ p(-1)= 1 - 2 + 1}}$

When we subtract 2 from 1 we get -1. -1 and 1 gets cancelled so give us ,

$\implies{\tt{ p(-1) = 0 }}$

$\large\boxed{\tt{ p(-1)= 0}}$

The remainder obtained when $\tt{ {x}^{2} + 2x + 1 }$ is divided by (-1)

Steps followed :

1. Here we have used the remainder theorem.
2. In simple words , remainder theorem works this way :

• Find the value of (x)
• Put it in the place of (x) in the whole equation
• Simplify them
• Get them to their simplest value till we get 1 value.
• The remainder which is of 1 value can be considered as the factor of the equation given.

Answer 2

Answer:

Step-by-step explanation:

ANSWER:

GIVEN:

x²+2x+1

With remainder as -1.

So first , we will place the value directly as

x = -1 ,

$(-1)^{2}+2(-1)+1$

$\implies 1 -2 +1$

$\implies 2-2 = 0$

So the remainder is zero.

Things to Remember:

• Always place the value when such question comes
• This is called REMAINDER THEOREM.

REMAINDER THEOREM:

Whenever we place a number with respect to x given in the equation, this method is called remainder theorem.