Question

the repulsive force betwwen two magnetic pole in air is 9×10^-3N.If the two poles are equal in strength and are seperated by a distance of 10cm.calculate pole strength of each pole?​

Answer 1

Answer:

Two magnetic poles of the same length attract each other with a force of 2N when placed on the two corners of an equilateral triangle. If a south pole of the same strength is placed at the third vertex, it experiences a force of magnitude.

Explanation:

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Answer 2

Answer:

30 NT^-1

Explanation:

The magnitude force between two poles is

F= k (Qm1×Qm2)/r^2

Given, F=9×10^-3 N , r=10 cm =10/100 m= 0.1 m

Now,

9×19^-3= 10^-7×(Qm^2/0.1^2)

solve the equation and get Qm= 30NT^-1