the required heat energy to convert 500 ML of water completely to vapour is ______ ( ) A) 27 k cal B) 270 k cal C) 54 k cal D) 540 k cal
Answers
Answer:
Amount of Heat energy Required = Mass × Latent heat of Vaporization. Latent heat of Vaporization of Water = 2260 J/kg. Thus, the amount of Heat energy required to convert Water at 100° C into vapor is 11300 Joules
Answer: 270 k cal of heat energy is required.
Explanation:
When water is at 100° C and we supply heat, all the heat goes into changing the state and the temperature remains constant.
The temperature changes only when all water has been converted into steam.
The heat supplied to water is not reflected in change in temperature and causes vaporization, hence it is termed as Latent heat of vaporization.
Density of water = 1 g/ml
Volume of water taken = 500 ml
Mass = Density × Volume
Therefore,
⇒ Mass of water taken = Density of water × Volume of water taken
⇒ Mass of water taken = 1 × 500 g
⇒ Mass of water taken = 500 g
Latent heat of vaporization of water = 540 cal/g
Heat supplied to water = Latent heat of vaporization × Mass of water
Heat supplied to water = 540 × 500 calorie
Heat supplied to water = 270000 calorie
Heat supplied to water = 270 kilo calorie
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