The required heat energy to convert 50ml of water completely to vapour
Answers
• water = 50ml
• convert into l = 0.005l
• now.., convert into m^3
• 0.005/100 m^3
• 0.0005m^3
• density of water = 1000
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☆ EXPLANATION
USING FORMULA
→ density = mass /volume
→ mass = density * volume
→ mass = 1000 * 0.0005
→ mass = 0.5 kg
☞ since, the initial temperature of water is not given
thus, let the temperature of water be 100°C
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☆ USING FORMULA
☞ amount of heat energy required
mass * latent heat of vaporization
Q = m * L
☞ latent heat of vaporization 2260 j/kg
→ Q = 0.5 * 2260
→ Q = 1130 j
☞ thus, the amount of heat energy required to convert water at 100°C into vapour is 1130 j
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☞ if the initial temperature of water will be given then we can calculate the heat as amount of heat energy temperature to bring the water from temperature t to 100°C
→ mass * C * Δt
→ thus, total heat = mCΔtQ
☞ by this formula temperature of heat can be easily calculated.....,
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