Question

the required heat energy to improve the temperature of 8 grams of ice from -10°c to -5°c​

Answer 1

-5 is the change in temperature

hope it helps you

Answer 2

Answer: 20 cal

Formula: Q= msΔT

Q= energy supplied

m= mass

s= specific heat capacity

ΔT= change in temp.

Step by step solution:

m=8g

S=1/2 cal/g/°C

ΔT= final temp. - initial temp.

   = -5 -(-10)

   = 5°C

Q= msΔT

Q= 8g*1/2 cal/g/°C*5°C

(crossing out things)

Q= 4*1 cal*5

Q= 20 cal

Hope it helps!!!