Question

The requirement of the house is 2 kW and the efficiency of the solar panel is 18%. Total solar panel installation area =

Answer 1

Given that,

Output power of the house is 2 kW

The efficiency of the solar panel is 18%

To find,

Total solar panel installation area.

Solution,

The formula used to find the total output power is given by :

Total power output = Total Area × Solar Irradiance × Efficiency

Solar Irradiance is a constant value of 1000 W/m²

A is the solar panel installation area

Rearranging the above formula o find area as follow :

$A=\dfrac{2\times 10^3}{100\times (18/100)}\\\\A=\dfrac{2\times 10^3\times 100}{1000\times 18}\\A=11.12\ m^2$

So, the solar panal instanllation area is $11.12\ m^2$/