Question

The requirement of the house is 2 kW and the efficiency of the solar panel is 18%. Total solar panel installation area =​

Answer 1

Step-by-step explanation:

Output power of the house is 2 kW

The efficiency of the solar panel is 18%

To find,

Total solar panel installation area.

Solution,

The formula used to find the total output power is given by :

Total power output = Total Area × Solar Irradiance × Efficiency

Solar Irradiance is a constant value of 1000 W/m²

A is the solar panel installation area

Rearranging the above formula o find area as follow :

\begin{gathered}A=\dfrac{2\times 10^3}{100\times (18/100)}\\\\A=\dfrac{2\times 10^3\times 100}{1000\times 18}\\A=11.12\ m^2\end{gathered}

A=

100×(18/100)

2×10

3

A=

1000×18

2×10

3

×100

A=11.12 m

2

So, the solar panal instanllation area is 11.12\ m^211.12 m

2

Hope it helps you.

Thank you for asking the question