Question

the resistance of 0.0025 M solution of k2so4 in 326 ohm the specific conductance of the solution if the cell constant is 4​

Answer 1

Given:

The resistance of K2SO4 solution, R = 326 Ω

The cell constant = 4​ m⁻¹

To Find:

The specific conductance of the given solution.

Calculation:

- We know the relation between the specific conductance, the cell constant and the resistance is:

Conductance = Cell constant / Resistance

⇒ κ = Cell constant / R

⇒ κ = 4 / 326

⇒ κ = 0.01227 S m⁻¹

⇒ κ = 1.227 × 10⁻⁴ S cm⁻¹

- So, the specific conductance of the given K2SO4 solution is 1.227 × 10⁻⁴ S cm⁻¹.

Answer 2

Answer:

______1.20 × 10^-2_______