Chemistry, asked by ashuthosh29, 8 months ago

the resistance of 0.01 M NaCl in a conductivity cell is 210 ohms the molar conductance of this solution is 4.5 *10^3 Scm2 mol^-1 calculate cell constant of the conductivity cell​

Answers

Answered by soul1899
1

Explanation:

Resistance of a conductivity cell filled with 0.1 M is 100 ohm. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of the 0.02 M KCl solution. Conductivity of 0.1 M KCl solution is 1.29*10-2 S cm-1

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