Chemistry, asked by prasadguturi96281, 9 months ago

The resistance of 0.1n acetic acid of 250 ohmwhen measured in a cell of cell constnt 1.15 cm-1

Answers

Answered by Anonymous
0

Answer:

We have Specific conductance,

k=Cell constant/resistance

=1.15/250

=23/5000 mho/m

Also we have,

Equivalent conductance = k*1000/N

= (23/5000)*1000

=4.6

Answered by rithvik301
0

Answer:

Explanation:

k=Cell constant/resistance

=1.15/250

=23/5000 mho/m

Also we have,

Equivalent conductance = k*1000/N

= (23/5000)*1000

=4.6

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