The resistance of 0.1n acetic acid of 250 ohmwhen measured in a cell of cell constnt 1.15 cm-1
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Answered by
0
Answer:
We have Specific conductance,
k=Cell constant/resistance
=1.15/250
=23/5000 mho/m
Also we have,
Equivalent conductance = k*1000/N
= (23/5000)*1000
=4.6
Answered by
0
Answer:
Explanation:
k=Cell constant/resistance
=1.15/250
=23/5000 mho/m
Also we have,
Equivalent conductance = k*1000/N
= (23/5000)*1000
=4.6
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