Question

the resistance of 1 conducting wire is 10 Omega. How much electric current will flow by connecting it with a battery of 1.5 volt ?​

Answer 1

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Answer 2

V=IR

V=1.5 V

R=10 ohm

I = ?

By applying above relation ..

I=V/R

I= 1.5/10

I= O.15 A