The resistance of 20 ohms,30 ohms and 40 ohms are connected in a series and once in parallel. Find equivalent resistance in two cases.
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Rs=R1+R2+R3
20+30+40=90
1/Rp=1/R1+1/R2+1/R3
1/20+1/30+1/40=6+4+3/120
=13/120
20+30+40=90
1/Rp=1/R1+1/R2+1/R3
1/20+1/30+1/40=6+4+3/120
=13/120
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