The resistance of a 0.5 M solution of an aqueous electrolyte enclosed between two platinum electrodes 1.5cm apart and having an area of 2.0cm^2 was found to be 30 ohm calculate the molar conductiviconductivity
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Explanation:
Gf949494
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Explanation:
the relationship between specific conductance and resistance is
k=1÷r*1÷a
=1÷30ohm×1.5÷2.0
=0.0225ohm-1 cm-1
the relationship between molar conductance and specific conductance is
^m=1000k÷c
=1000×0.0225÷0.5
=45onm-1cm-1mol-1
=0.0045ohm-1cm-1mol-1
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