The resistance of a 5 cm long wire is. It
is uniformly stretched so that its length
becomes 20 cm. The resistance of the
wire is :
Answers
Answered by
0
Answer:
the resistance of wire will be doubled.
Answered by
0
Answer:Resistance of wire will be
20 Ω
Explanation:
Resistance of a wire is given by the formula
R
=
ρ
l
A
R
=
ρ
l
A
=
ρ
l
A
×
(
l
l
)
=
ρ
l
2
A
l
=
ρ
l
2
V
From above relation,
R
∝
l
2
[∵ Resistivity (ρ) and Volume (V) of wire will be same even after stretching].
R
2
R
1
=
(
l
2
l
1
)
2
R
2
=
R
1
×
(
l
2
l
1
)
2
R
2
=
5 Ω
×
(
40
cm
20
cm
)
2
R
2
=
20 Ω
Explanation:
Similar questions