The resistance of a bulb filament is 100 ohm at a temperature of 100 degrees centigrade . If it's temperature coefficient of resistance be 0.005 per degree centigrade , it's resistance will become 200 ohm at a temperature of
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resistance and temperature are related
R = R°( 1+ a∆T)
where R is final resistance, R° is initial resistance , a is lonear co-efficient , and ∆T is temperature change .
now,
200 = 100{ 1 + 5 × 10-³( T-100) }
2 = 1 + 5 × 10-³ ( T-100)
0.2 × 10³ = T -100
T = 200 +100 = 300° C
R = R°( 1+ a∆T)
where R is final resistance, R° is initial resistance , a is lonear co-efficient , and ∆T is temperature change .
now,
200 = 100{ 1 + 5 × 10-³( T-100) }
2 = 1 + 5 × 10-³ ( T-100)
0.2 × 10³ = T -100
T = 200 +100 = 300° C
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