The resistance of a certain platinum resistance thermometer is found to be 2.56 at 00C and 3.56at 1000C. When the thermometer is immersed in a given liquid, its resistance is observed to be 5.06. The temperature of the liquid is
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Solution
We know that,
R
T
=R
0
+α(T
1
−T
0
)
If T
0
=0
∘
C,T
1
=100
∘
C,R
0
=2.56Ω
and R
T
=3.56Ω. Then,
3.56=2.56+α(100−0)
100
1
=α
Let T
L
be the tan P of liquid,
Then, 5.06=2.56+
100
1
(T
L
−0)
⇒2.5×100=T
L
T
L
=250
∘
C
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