Question

The resistance of a column having diameter 1.0 cm and the length 50 cm containing solution

of 0.05 mol L1- NaOH is 5.55 X 103 ohm, then calculate its resistivity, conductivity and molar

conductivity.​

Answer 1

Explanation:

A=πr^2 =3.14×(0.5)^2 =0.785cm^2 ,l=50cm

R= ρl/A ρ =AR/1 = 5.55×10 ^−3×0.785/50

ρ=87.18 Ωcm

Conductivity, K= 1/ρ =0.01147Scm ^−1

Molar Conductivity = 1000×K/C = 0.01147×1000/0.05

Λ m =229.4 Scm^2 mol^ −1

Molar conductivity, ΛΛ =229.4 Scm^2mol −1

Hope It Helps