Question

The resistance of a conducting cell constant 10^-3 M Kcl solution at 25°c is 1500 ohm what is cell constant if conductivity of 10^-3 M Kcl at 25° is 1.5×10^-4 ohm^-1 cm^-1

Answer 1

Answer:

0.219

Explanation:

R=1500 Ω (Resistance)

k=1.46×10

−4

Scm

−1

(Conductivity)

T=298 K

We will use the formula,

k=Gx

where k is conductivity

G is

R

1

x is cell constant

1.46×10

−4

=

1500

1

×x

1.46×10

−4

×1500=x

0.219 cm

−1

=x

The cell constant is 0.219 cm

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