Question

The resistance of a conducting wire X of length 1 m is 5ohm. Calculate the resistance of the wire made with the same material whose length is 4 times and area of cross section is 5 times that of wire X ( At same temperature )​

Answer 1

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Answer 2

let resistivity be x ohm m

we know that R= resistivity × l/A

R1 = 5 ohm

l1 = 1 m

resistivity = x ohm metre

a = ?

so, 5 = x1/a

a = x/5 m²

now,

R2 = ?

a2 = 5 (x/5)

= m²

l2 = 4 (1)

= 4 m

therefore the new resistance is

R2 = $\frac{x}{ \frac{x}{5} }$

R2 = 5 ohms

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