The resistance of a conducting wire x of length 1m is 5ohm . Calculate the resistance of wire made by the same material whose length is 4 time s and area of cross section is 5times that of wire x .at same Temperature.
Answers
Answered by
2
Answer:
4 ohm
Explanation:
R=kl/A
In the first case R=5 ohm
l=1m
In the second case let R=R1
l=4l, A=5A
By taking the ratio R/R1, we get
R1/R=4/5
R1=4 ohm
Answered by
5
Answer:
4 Ω
Explanation:
rho = RA/L
In this first case, R= 5 Ω length = L Area = A
R = rhoL/A
5 = rho(1)/A
rho = 5A
Note : There's no temperature change
In the second case, R = ? Length = 4L Area = 5A
R = rho(4)/5A
= 4/5 x rho/A
= 4/5 x 5A/A
= 4/5 x 5
R = 4Ω
Hope this helps
Good luck for boards :)
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