The resistance of a conducting wire x of length 1m is 5ohm.Calculate the resistance of wire made by the same material whose length is 4 times and area of cross-section is 5 times that of wire x (At same temperature)
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Explanation:
Let the resistance of wire X be R1.
L = 1m
R1 = 5ohm
=> 5 = (Rho)L/A.....(1)
Now ATQ,
R2 = (Rho)(4L)/(5A)
or R2 = (Rho)(L/A)×4/5
or R2 = 5×4/5 (from 1)
or R2 = 4Ohm...... Answer
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