Question

The resistance of a conductivity cell containig 0.1MKCl solution at 298K is 1500Ohm.what is the cell constant if the conductivity of 0.01M KCl solution at 298K is 0.146×10-3Scm-1?

Answer 1

Hey !!

Conductivity (κ) = 1 / Resistance (R) × Cell Constant

κ = 0.146 × 10⁻³ S cm⁻¹ , R = 1500 Ω

       0.146 × 10⁻³ S cm⁻¹ = 1 / 1500 Ω × Cell constant

∴ Cell constant = 0.146 × 10⁻³ S cm⁻¹ × 1500 Ω

           = 219 × 10⁻³ cm⁻¹

           = 0.219 cm⁻¹

Hope it helps you !!