the resistance of a conductor is 4 if it is stretched such that its diameter becomes half of its initial diameter then find the value of its final resistance
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Explanation:
Resistance is inversely proportional to square of diameter
Let the initial area be A=πD
2
/4
Final D is D/4 So new area is A
f
=π×D
2
/32=A/16
Now L
f
A
f
=LA , So F
f
=16L
Rf=ρ
A
f
L
f
=ρ
A
256L
=256R
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