Question

The resistance of a conductor is 592. A current of 3A passes through it for 20 sec. The heat produced in the.conductor will be:
(i) 900 joule
(ii) 900 calorie
(iii) 300 joule
(iv) 300 calorie​

Answer 1

Answer:

I) 900 Joule I hope it will help you

Answer 2

Explanation:

here R=5 not 592

H=I^2×R×T

H=3^2×5×20

H=9×5×20

H=900Joule