The resistance of a conductor is 592. A current of 3A passes through it for 20 sec. The heat produced in the.conductor will be:
(i) 900 joule
(ii) 900 calorie
(iii) 300 joule
(iv) 300 calorie
Answers
Answered by
7
Answer:
I) 900 Joule I hope it will help you
Answered by
2
Explanation:
here R=5 not 592
H=I^2×R×T
H=3^2×5×20
H=9×5×20
H=900Joule
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