Question

the resistance of a copper wire is 10 ohm .If its length is halved keeping cross sectional area what will be new resistance​

Answer 1

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Answer 2

Answer:

The new resistance (r) = $40 ohm$

Explanation:

• The ratio of the potential difference across a conductor to the current flowing through a conductor is called the resistance of an object.
• A non-ferrous metallic mineral is copper. It is a significant metal first used by humans. In nature, copper can be found in its natural state.

$R=resistivity*\frac{length}{area}$

Resistance of copper wire =$10 ohm$

$Resistivity=10*(area/length)$$Resistivity=10*(\frac{area}{length} )$

Resistivity = (k) metarial property

K= constant

As a result, new resistance r

$r =resistivity*\frac{2 length}{5 area}$

By value of resistivity here we get

$r=10*(\frac{area}{length} )*(\frac{2 length}{5area} ) ohm$

Therefore, the resistance (r) = $40 ohm$

To learn more about resistance,visit:

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https://brainly.in/question/25200496

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