The resistance of a Cu wire 200meter long is 21omega if its thickness is 0.44mm calculate its specific resistance in ohm meter
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Answer: 0.0462ohm-meter IS THE ANSWER
Explanation:
GIVEN, R=21 ohm
A=0.44mm²=0.44×10⁻⁶m²
l=200m
R=ρl/A
HERE ρ=SPECIFIC RESISTANCE
l=LENGTH OF THE WIRE
A=THICKNESS OF AREA
==>21=ρ×200/0.44×10⁻⁶==>ρ=21×0.44×10⁻⁶/200=0.0462ohm-meter
HOPE IT HELPS YOU.............
THANK YOU.
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