Question

The resistance of a galvenometer is
100 ohm and maximum current which
can pass through 0.001 A.
The
value of
shunt to change
galvanometer into voltmeter of 12 volt range will be :
1. 12100 ohm
2. 11900 ohm
3. 1190 ohm
4. 11999 ohm
Om symbol ​

Answer 1

Answer:

V= iR

given: i= 0.001 A

R= 100

V = 0.001×100

V = 0.1

100 ohm for 0.1 V

for 1 V = 100/0.1

1V = 1000

12 V = 12000 ohm.

option 4 is the answer...

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Answer 2

Step-by-step explanation:

Given: A galvanometer of 100 resistance gives full scale deflection with 0.01A current

To find the resistance that should be connected convert it into an ammeter of range 10A

Solution:

Galvanometer is a very sensitive instrument therefore it cannot measure heavy currents. In order to convert a Galvanometer into an Ammeter, a very low shunt resistance is connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes through the shunt.

If resistance of galvanometer is R

g

and it gives full-scale deflection when current I

g

is passed through it. Then,

V=I

g

R

g

⟹V=0.01A×100Ω

⟹V=1V

Let a shunt of resistance (R

s

) is connected in parallel to galvanometer. If total current through the circuit is I.

I=10A=I

s

+I

g

V=I

s

R

s

=(I−I

g

)R

s

(I−I

g

)R

s

=I

g

R

g

(10−0.01)R

s

=100×0.01

⟹R

s

=0.1Ω

is the resistance that should be connected in parallel to convert it into an ammeter of range 10A