Question

The resistance of a resistor is reduced to
half of its initial value. In doing so, if other
parameters of the circuit remain unchanged,
the heating effects in the resistor will become
(a) two times (b) half
(c) one-fourth
(d) four times

Please Solve with Both
H= i²rt
H=v²/r t
h = i {}^{2}rth=i
2
rt
h = \frac{ {v}^{2} }{r} \times th=
r
v
2

​
×t​

Answer 1

Answer:

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