The resistance of a train weighing 10⁵kg moving at a speed of 72km/h is 5gwt/kg . Find the rate at which the engine is doing work . The engine consumed 400 kg of coal per hour and burning of 1kg off coal produces 1.44×10⁷J .What portion of this energy is usually employed ?
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Step-by-step explanation:
Answer
Frictional force=0.5kgf=
100
5
×10
6
=50000N
Uniform speed=36kmph=36×
18
5
=10m/s
Power of engine is given by,
Power=Fv
=50000×10
=500000watt
=500kw
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