Math, asked by nickname0606, 4 months ago

The resistance of a train weighing 10⁵kg moving at a speed of 72km/h is 5gwt/kg . Find the rate at which the engine is doing work . The engine consumed 400 kg of coal per hour and burning of 1kg off coal produces 1.44×10⁷J .What portion of this energy is usually employed ?​

Answers

Answered by Anu10000
1

Step-by-step explanation:

Answer

Frictional force=0.5kgf=

100

5

×10

6

=50000N

Uniform speed=36kmph=36×

18

5

=10m/s

Power of engine is given by,

Power=Fv

=50000×10

=500000watt

=500kw

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