the resistance of a wire at ice points is 5 ohm and at steam point. it is 5.3 ohm when the wire is inserted in a hot bath the resistance is 5.6 ohm calculate the temperature of hot bath
Answers
Answered by
4
Dear Sumit,
● Answer -
T = 200 °C
● Explanation -
# Given -
R0 = 5 ohm
R100 = 5.3 ohm
Rb = 5.6 ohm
# Solution -
Temperature of hot bath is calculated by formula -
T = 100 (Rb-R0) / (R100-R0)
T = 100 × (5.6-5) / (5.3-5)
T = 60 / 0.3
T = 200 °C
Therefore, temperature of hot bath is 200 °C.
Hope this helped...
● Answer -
T = 200 °C
● Explanation -
# Given -
R0 = 5 ohm
R100 = 5.3 ohm
Rb = 5.6 ohm
# Solution -
Temperature of hot bath is calculated by formula -
T = 100 (Rb-R0) / (R100-R0)
T = 100 × (5.6-5) / (5.3-5)
T = 60 / 0.3
T = 200 °C
Therefore, temperature of hot bath is 200 °C.
Hope this helped...
Answered by
3
the resistance of a wire at ice points is 5 ohm and at steam point. it is 5.3 ohm when the wire is inserted in a hot bath the resistance is 5.6 ohm calculate the temperature of hot bath
ice point = 0 deg
steam point = 100 deg
delta T = 100
alpha
R100 = R0 (1 + alpha deltaT)
5.3 = 5(1+ alpha 100)
5.3 = 5 + alpha500
alpha = 0.3/500
alpha = 0.006
RT = R0(1 + alphaT)
5.6 = 5 + 5(0.006)T
0.6 = 0.003T
T = 0.6/0.003
T = 200 deg
Similar questions