Question

the resistance of a wire at room temperature 30° c is found to be 10 home now to increase the resistance by 10% the temperature of wire must be[ the temperature coefficient of resistance of the material of the wire is 0.00125 per °c]​

Answer 1

Answer:

B) 1100K

Explanation:

Initial temperature of the wire = 27°C (Given)

Initial resistance of the wire = 1 (Given)

Temperature coefficient of the wire = (1.25 10-3)c-1 (Given)

Resistance of wire is a linear function of temperature.

Therefore,

α = ΔR / (RΔθ)

Δθ = ΔR / (Rα)

(T - 27) = (2 Ω - 1 Ω) / (1 Ω × 0.00125 /°C)

T - 27 °C = 800 °C

T = 27 °C + 800°C

T = 827 °C

T = (827 + 273) K

T = 1100 K

Thus, the resistance of the wire will be 2 ohm at 1100 K.

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Answer 2

Answer:

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Explanation:

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