The resistance of a wire having a length of 0.6 and diameter 0.4 mm is 1.5 Ω. Find the resistivity of its material.
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Answer:
Resistance = 3 Ohm
length = 1.2m
diameter = 0.4mm=0.4×10−3
Resistivity = ?
R = APl
R=πd2ρl
R = resistance ,P= resistivity , l = length d = diameter
3=π×0.4×10−3×0.4×10−3ρ×1.5×4ρ=63×π×0.4×0.4×10−6ρ=8π×10−8Ωm
Explanation:
hope it helps you from my side
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