The resistance of a wire is 10 ohm if its length is incresed by 10%by stretching
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The resistance of a wire is 10 ohm. It`s length is increased by 10% by stretching. The new resistance will be(1)12ohm (2) 1.2ohm (3)1.3ohm (4)1.1ohm
As Resistance is directly proportional to the length of the resistance wire,
R = kl^2
After length gets increased by 10% we get,
R’ = k(l + 0.l)^2
divide both we get,
R/R’ = 1/(1.1)^2 => 1/1.21
R’ = 1.21 R ohm
2option is correct
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Let new R = y
Let the original length = x
New length is 10% increased
=> x +
=> x +
=> +
=>
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