The resistance of a wire is 20 ohm .what will be new resistance, if it is stretched uniformly 8 times it's original length?
Answers
Answered by
5
Answer:
R' = 160 ohm
Explanation:
R = rho L / A
R will also become 8 times
so R' = 160 ohm
Answered by
13
Answer:
The new resistance will be 1280 ohm.
Explanation:
The resistance of the wire is given as
Here, L is the length of the wire, A is the area of the wire and is the resistivity of the wire.
Now new length of the wire, l = 8L.
If a be the new cross-sectional area, then
a l = AL (as volume of the wire remain constant)
a (8 x L) = AL
a = A/8.
Therefore, new resistance of the wire
Or,
Given R = 20 ohm.
So,
r = 1280 ohm.
Thus, the new resistance will be 1280 ohm.
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