the resistance of a wire is proportional to its length and inversely proportional to the square of its radius , two wires of the same material have the same resistance and their radii are in the ratio 9:8 . if the length of first wire is 162 cms. find the length of other wire.
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Answered by
2
R2R1=(ρ2ρ1)(L2L1)(A1A2)
=(ρ2ρ1)(L2L1)(r12r22)
=32×53×(72)−2[r1r2=27]
=52×(494)−2
=52×449
R2R1=1049
Answered by
0
Step-by-step explanation:
R2R1=(ρ2ρ1)(L2L1)(A1A2)
=(ρ2ρ1)(L2L1)(r12r22)
=32×53×(72)−2[r1r2=27]
=52×(494)−2
=52×449
R2R1=1049
I hope it's help you
rajdeep9713:
this is maths question not physics
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