The resistance of a wire of 0.01 cm radius is 10ω. if the resistivity of the material of the wire is 50 × 10−8 ohm meter, find the length of the wire.
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given , radius of the word (r)= 0.01cm =1×10^-4m
resistance of the wire (R)=10 ohm
resistivity of the material (ρ)= 50×10^-8 ohm-meter
then, we know that,
R =( ρ × L)/A
hence, L=( R×A)/ρ
SO,
L= 10×(π×r^2)/(50×10^-8)
L= [10×3.14×(1×10^-4)^2]/50×10^-8
so, L= 0.628m= 62.8 cm
resistance of the wire (R)=10 ohm
resistivity of the material (ρ)= 50×10^-8 ohm-meter
then, we know that,
R =( ρ × L)/A
hence, L=( R×A)/ρ
SO,
L= 10×(π×r^2)/(50×10^-8)
L= [10×3.14×(1×10^-4)^2]/50×10^-8
so, L= 0.628m= 62.8 cm
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