The resistance of a wire of 0.01 cm radius is 10 ohm. If the resistivity of the material of the wire is 50x10^-8 ohm-meter, find the length of the wire..
Don't give foolish answer, answer only when you know the correct solution,, I am very serious and need the answer urgent
So please solve this and solve as easily and expand fully so I can understand it easily
Please
ayushSharma111:
solve only if u know the proper solution
Answers
Answered by
33
Resistance = Resistivity × Length /Area
Now
l = R × A / p
l = 10 π ( 1 × 10^-4)square/ 50 × 10^-8
l = 10 × 3.14 ( 1 × 10^-4)^2/ 50 × 10^-8
l = 314/500
l = 0.628 metre Ans....
Hope it will be helpful
Now
l = R × A / p
l = 10 π ( 1 × 10^-4)square/ 50 × 10^-8
l = 10 × 3.14 ( 1 × 10^-4)^2/ 50 × 10^-8
l = 314/500
l = 0.628 metre Ans....
Hope it will be helpful
(1*10^-4) pe ^2 kyu aaya
Because area of cross section is in circular shape so pi radius square.
This is the formula of area
but radius to 0.01 h
yeah but first our approach is to convert 0.01 cm into metre
So we will get 0.01 × 10^-2 metre radius
oh
thank you yaar
thanks you very much
its ok..
Answered by
4
Given,
radius 0.01cm is 0.01*10^-2 metre
Resi.. 10 ohm,
rho (p) is 50*^-8 ohm metre.
we know that R is equal to p(l)/A
area is pie r^2
Then
R A /p is length
Pie r^2(R)/p equal to l
3.14* 0.01*10^-2 0.01*10^-2* 10 ohm/ 50* 10^-8
And equal to ,
L equals to 3.14*0.0001*1*10^4
L equals to 3.14*1
L equal to 3.14
radius 0.01cm is 0.01*10^-2 metre
Resi.. 10 ohm,
rho (p) is 50*^-8 ohm metre.
we know that R is equal to p(l)/A
area is pie r^2
Then
R A /p is length
Pie r^2(R)/p equal to l
3.14* 0.01*10^-2 0.01*10^-2* 10 ohm/ 50* 10^-8
And equal to ,
L equals to 3.14*0.0001*1*10^4
L equals to 3.14*1
L equal to 3.14
sorry bro but it is wrong
Similar questions