The resistance of a wire of 0.01cm radius is 10ohms .if the resistivity of the material is 50 *10 to the power of -8 .find the length of the wire .(the and given before is wrong .how can the radius be 10 to the power -4:-( )
Answers
Answered by
3
Thus so
_________
___________________________________@g ___________________________________
GIVEN
RESISTANCE = 10 OHM
. RADIUS = 0.01 CM = 1 / 100 CM
THEN
➿ R = p L / A
. 10 = 5 / 10 ^ 7 * L / 22 / 7 * 1 / 10 ^ 4
. L = 10 ^ 5 * 11 / 175
L = 10 ^ 6 / 159 CM
.
_________
___________________________________@g ___________________________________
GIVEN
RESISTANCE = 10 OHM
. RADIUS = 0.01 CM = 1 / 100 CM
THEN
➿ R = p L / A
. 10 = 5 / 10 ^ 7 * L / 22 / 7 * 1 / 10 ^ 4
. L = 10 ^ 5 * 11 / 175
L = 10 ^ 6 / 159 CM
.
Answered by
1
resistance of wire , R = 10 ohm
radius of base of wire , r = 0.01cm = 0.01/100 m
r = 1 × 10^-4 m
base area , A = πr² = 3.14 × (10^-4)² = 3.14 × 10^-8 m²
resistivity of the material of wire , ρ = 50 × 10^-8 ohm.meter
we know, formula
R = ρL/A
L = RA/ρ
= 10 ohm × 3.14× 10^-8m²/50 × 10^-8 ohm.meter
= 31.4/50 m
= 0.628 m
hence, length of wire is 0.628 m
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