Question

The resistance of a wire of length 10 m
is 2 ohm. If the area of cross section of the
wire is 2 x 10 m, determine its (i) resistivity
(ii) conductance and (iii) conductivity​

Answer 1

Answer:

sorryyy...

Explanation:

I don't like maths

Answer 2

Answer:

(i) Resistivity - $\sf{4\:×\:10^{-8}}$

(ii) Conductance - 0.5 mho

(iii) Conductivity - $\sf{0.25\:×\:10^{8}}$

Explanation:

Given Data :-

Length of the wire, l = $\sf{10\:m}$

Resistance, R = $\sf{2\:ohm}$

Area of cross section, A = $\sf{2\:×\:10^{-7}m²}$

(i) Resistivity, $\sf{ρ\:=\:{\dfrac{RA}{l}}}$

$\sf{⟹\:ρ\:{\dfrac{2\:×\:2\:×\:10^{-7}}{10}}}$

$\sf{⟹\:4\:×\:10^{-8}}$

(ii) Conductance, $\sf{G\:=\:{\dfrac{1}{R}}}$

$\sf{⟹\:G\:=\:{\dfrac{1}{2}}}$

$\sf{⟹\:G\:=\:0.5\:mho}$

(iii) Conductivity, $\sf{σ\:=\:{\dfrac{1}{ρ}}}$

$\sf{⟹{\dfrac{1}{4\:×\:10^{-8}}}}$

$\sf{⟹{\dfrac{0.25}{10^{-8}}}}$

$\sf{⟹{0.25\:×\:10^{8}\:mhom^{-1}}}$