The resistance of a wire of length 100 cm and uniform area of cross-section 0.020 sq.cm, is found to be 2.0 ohm. Calculate specific resistance of wire.
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Answers
Answered by
119
Answer :-
Specific resistance/resistivity of the wire is 4 × 10⁻⁶ Ωm .
Explanation :-
We have :-
→ Length of the wire = 100 cm = 1 m
→ Area of cross section = 0.02 cm²
→ Resistance = 2 Ω
________________________________
Firstly, let's convert the area of cross section of the wire from cm² to m² .
⇒ 1 cm² = 10⁻⁴ m²
⇒ 0.02 cm² = 0.02 × 10⁻⁴ m²
⇒ 2 × 10⁻⁶ m²
________________________________
Now, we know that :-
R = ρl/A
Where :-
• R is resistance.
• ρ is specific resistance.
• l is length of the wire.
• A is area of cross section.
Substituting values, we get :-
⇒ 2 = (ρ × 1)/2 × 10⁻⁶
⇒ ρ = 2 × 2 × 10⁻⁶
⇒ ρ = 4 × 10⁻⁶ Ωm
Answered by
148
I=100cm=1m
area=0.02=0.000002m^2
specific resistance (Rxarea)/length
2×0.000002×1
=4x10^-6ohm-m
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