The resistance of a wire of length 250 m is 1 ohm. If the resistivity of the material of wire is 1.6 x 10–8 ohm meter, find the area of cross-section of the wire. How much does the resistance change if the diameter is doubled?
Answers
Answered by
3
answer is given in the picture plz check and thanks for asking
Attachments:
Answered by
2
hey bro/gal.
since, resistance = resistivity× length / area
=) 1 = 1.6 * 10^-8 * 250/ A
=) A = 400*10^-8 = 4*10^-6 m²
=) if diameter is doubled then area will become 4A.
=) new Area = A' = 4*4*10^-6 = 16*10^-6 m²
=) R' = 1.6*10^-8 * 250/ 16*10^-6
= 1/4 ohm.
since, resistance = resistivity× length / area
=) 1 = 1.6 * 10^-8 * 250/ A
=) A = 400*10^-8 = 4*10^-6 m²
=) if diameter is doubled then area will become 4A.
=) new Area = A' = 4*4*10^-6 = 16*10^-6 m²
=) R' = 1.6*10^-8 * 250/ 16*10^-6
= 1/4 ohm.
Similar questions