the resistance of a wire of length 300 m and cross _section area 1.0mm^2 made of material of resistivity 1.0×10^-7
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Answered by
6
hello friend...!!!
• According to the question, we should calculate the resistance of the material,
• Resistance R = ΦL / A
here, Φ represents resistivity, L represents length and A represents Area
• given : L = 300 m
A = 1 mm^2 = 1 X 10^-6 m
Φ = 1 X 10^-7
therefore, Resistance is
R = ( 1 X 10^-7 X 300 ) / 1 X 10^-6
R = 300 X 10^-7 X 10^6
R = 300 X 10^-1
therefore,
R = 30 ohm.
the resistance of the given material is 30 ohm.
_________________________________
hope it helps...!!!
• According to the question, we should calculate the resistance of the material,
• Resistance R = ΦL / A
here, Φ represents resistivity, L represents length and A represents Area
• given : L = 300 m
A = 1 mm^2 = 1 X 10^-6 m
Φ = 1 X 10^-7
therefore, Resistance is
R = ( 1 X 10^-7 X 300 ) / 1 X 10^-6
R = 300 X 10^-7 X 10^6
R = 300 X 10^-1
therefore,
R = 30 ohm.
the resistance of the given material is 30 ohm.
_________________________________
hope it helps...!!!
Answered by
10
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