Physics, asked by NAMANISheretohelp, 10 months ago

the resistance of an electric bulb drawing 1.2a at 6v will be

Answers

Answered by aasarafood24
5

Answer:

Given

v=6volt

I=1.2a

R=V/R

R=6/1.2=5columbs

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Answered by ItzAditt007
4

Your Answer is 5 ohm.

ExplnaTion:-

Given:-

  • Current drawn by an electric bulb at potential difference of 6 Volts(V) = 1.2 Amphere (A)

To Find:-

  • The resistance of the electric bulb.

Law Used:-

Ohm's Law

 \\ \\ \tt\longrightarrow V = IR.\\ \\

Where,

  • V = Potential Difference.

  • I = Current.

  • R = Resistance.

So Here,

  • V = 6 V.

  • I = 1.2 A.

  • R = ?? [To Find].

Therefore,

Lets put the value in above formula:-

\\ \\ \tt\mapsto V = IR. \\ \\ \tt\mapsto 6 \:\:V = 1.2\:\;A \times R. \\ \\ \tt\mapsto R = \dfrac{6 \:\:V}{1.2\:\: A}.\\ \\ \tt\mapsto R = \frac{5 \:\:V}{A}. \\ \\ \tt\mapsto R = 5\:\:\:\:Ohm.\\ \\

Therefore the resistance of the bulb is 5 ohm.

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