The resistance of an electric wire of an alloy is 10 ohm .if the thickness of the wire is0.001m, length is 1m find its resistivity
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Answer:
The given information are:
Resistance(R)=10Ω,
length(L)=1m,
Diameter=0.001m,
Radius (Diameter/2)=0.005m.
The area of the cross section of the wire is
π r^2 Or, A = 3.14 x (0.005)^2 m^2 Or,
A = 0.0000785 m^2.
We know that, ρ= (R*A)/L.
Therefore,
ρ= (10Ω*0.0000785)sqm / 1m.
ρ=10Ω*0.0000785. ρ=0.000785Ωm.
Therefore, the resistance is 0.000785Ωm.
Step-by-step explanation:
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