the resistance of bulb at 30 degrees is 30 ohms. Find at 0 degree Celsius.
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Answer:-
Given: The resistance of a conductor at 20∘C is 3.15Ω and at 100∘C is 3.75Ω.
To find the temperature co-efficient of resistance of the conductor.
Solution:
Here R20=3.15,R100=3.75
We know that Rt=R0(1+αt)
where R0= resistance at 0∘C
and Rt= resistance at t∘C
α= temperature coefficient of resistance
Now,
R20=3.15=R0(1+20α)....(i)
R100=3.75=R0(1+100α)....(ii)
Dividing (i) and (ii), we get
R0(1+100α)R0(1+20α)=3.753.15⟹3.75(1+20α)=3.15(1+100α)⟹3.75+75α=3.15+315α⟹240α=0.6⟹α=0.0025∘C−1
From equation(i) ,
R0=1+20α3.15⟹R0=1+20(0.0025)3.15⟹R0=1+0.053.15⟹R0=3Ω
is the temperature co-efficient of resistance of the conductor.
Hope it works..!!
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