Chemistry, asked by rvgk93, 10 months ago

The resistance of cell containing 0.1 N KCl solution and 0.1 N AgNO3 solution was 337.62 ohms and 362.65 ohms respectively at 298 K. The conductivity of 0.1 N KCl is 0.01286 ohm-1cm-1 at 298K. Find the cell constant and equivalent conductance of 0.1 N AgNO3 solution.

Answers

Answered by MATM25
0

Answer:

                      Mark me as brainliest

Explanation:

κ = GG* where κ = specific conductance = 0.0112ohm-1cm-1 G = conductance = 155 = 0.01818ohm-1 G* = cell constant 0.0112 = 0.01818 × G* ... The resistance of the cell containing the solution at the same temperature was found to be 55 ohm. The cell constant will be: ... where κ=specificconductance=0.0112ohm−1cm−1.

Similar questions